Problem 1:
-8 %26lt; -(sq root)40 %26lt; -7
TRUE OR FALSE?
Problem 2:
9 %26lt; 3(sq root)51 %26lt; 10
TRUE OR FALSE?Is the math statement true or false?
- 8 %26lt; 鈭?0 %26lt; - 7
-8 %26lt; 鈭? 鈭?0 %26lt; - 7
-8 %26lt; 2 鈭?0 %26lt; - 7
-8 %26lt; 2 x 3.16227766 %26lt; - 7
- 8 %26lt; 6.32455532 %26lt; - 7
This above statement is FALSE
- - - - - - - - - - - - - - - - - - - - -
9 %26lt; 鈭?51 %26lt; 10
9 %26lt; 鈭? 鈭?0 %26lt; 10
9 %26lt; 鈭? 鈭? 鈭?5 %26lt; 10
9 %26lt; 1 x 1,414213562 x 5 %26lt; 10
9 %26lt; 7.071067812 %26lt; 10
The above statement is FALSE
- - - - - -S-Is the math statement true or false?
the square root of 40 is between 6 (36) and 7 (49)... so the first problem is false because it would be %26gt; -7 also.
The square root of 51 is between 7 (49) and 8 (64)... so the second problem is also false because 3*sqroot 51 would be between 21 and 24... which is %26gt;10.
Don't know, don't care, I passed math when i was in school the old fashioned way. I copied off my nerdy friend!
i'm not sure that these are set up as usable equations-
Of course, it's false. Because when -8 %26lt; -(sq root)40 %26lt; -7 is squared we got 64 %26gt; 40 %26gt; 49 which is also false. Now therefore, the above statement of yours is false.
2nd reason, the negative square root of 40 is greater than -7.
Problem 2.
9 %26lt; 3(sq root)51 %26lt; 10 will become 9 %26lt; 21.4242852 %26lt; 10 which is also a false.
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